Tile Work Cost in Lake Alfred, FL in 2026
Most Tile Work projects in Lake Alfred, FL cost between $1,500 and $6,000. The typical price is $3,100.
Labour and materials in Lake Alfred run about 6% below the national average. These figures are adjusted for that, so they are not the national average you will find elsewhere.
What drives the price
- Tile size and material — ceramic, porcelain or natural stone
- Pattern complexity: straight lay versus herringbone
- Substrate prep and waterproofing
- Demolition of the existing surface
Usually included
- Tile, thinset, grout and sealer
- Substrate prep and waterproof membrane
- Layout, cutting and setting
Usually extra
- Subfloor replacement
- Plumbing fixture relocation
Unit prices in Lake Alfred, FL
| Quality tier | Cost per sq ft |
|---|---|
| Budget | $7.65 |
| Mid-range | $15 |
| High-end | $31 |
Tile installers in Lake Alfred, FL
Businesses listed on Google near Lake Alfred, FL. We are not affiliated with them and do not vet them — always confirm licensing and insurance before hiring.
Blackburn's Interiors
4.8(77 reviews)
1507 Havendale Blvd NW, Winter Haven, FL 33881
Elixir Flooring And Tile
5.0(4 reviews)
235 Commonwealth Ave N, Polk City, FL 33868